12 Jul 2026

Reading the Exceptional-Point Project V: Complete Notation and Crossover Guide

exceptional-points paper-notation crossover-scaling dimensional-analysis research-reading

This post is a self-contained guide to the notation and main calculation in the paper Structured-to-generic crossover at arbitrary-order exceptional points in supersymmetric $\mathcal{PT}$-symmetric arrays.

It explains how the expressions in the manuscript are connected, with special attention to

\[\boxed{ |\delta_c|\asymp \frac{2^{N-2}}{(N-1)!} \frac{|q|^{N/2}}{|\Omega|^{N-1}} }.\]

The reader is assumed to know the basic meaning of $\mathcal{PT}$ symmetry and supersymmetry. Everything else needed for this formula is developed below.

1. The Physical Model in One Line

The ideal array Hamiltonian is

\[H_N(\Omega,\gamma) =\Omega J_x+i\gamma J_z.\]

It describes $N$ coupled modes. The spin label is

\[j=\frac{N-1}{2},\]

so the $J_z$ quantum number takes the values

\[m=-j,-j+1,\ldots,j.\]

The nearest-neighbour coupling between sites $n$ and $n+1$ is

\[C_n= \frac{\Omega}{2}\sqrt{n(N-n)}, \qquad n=1,\ldots,N-1.\]

The diagonal gain-loss gradient is supplied by $i\gamma J_z$.

2. Master Notation Table

Array and spin labels

Symbol Definition Meaning
$N$ $N=2j+1$ number of modes or sites
$j$ $(N-1)/2$ spin representation
$n$ $1,\ldots,N$ physical site index
$m$ $-j,\ldots,j$ structured-mode label
$J_x,J_y,J_z$ spin-$j$ matrices algebraic representation of the array
$C_n$ $\frac{\Omega}{2}\sqrt{n(N-n)}$ coupling of bond $n$

Physical control parameters

Symbol Definition Meaning
$\Omega$ common coupling scale controls all designed bonds
$\gamma$ gain-loss scale controls the imaginary diagonal gradient
$J$ critical value with $\Omega=\gamma=J$ exceptional-point scale
$\epsilon$ $\Omega=J+\epsilon$ structured coupling displacement
$\delta$ coefficient of $V_\delta$ terminal structure-breaking coupling
$q$ $\Omega^2-\gamma^2$ signed structured distance from the EP

Polynomial and crossover quantities

Symbol Definition Meaning    
$P_N(E;q,\delta)$ $\det(EI-H_N-V_\delta)$ full characteristic polynomial    
$P_N^{(0)}(E;q)$ $P_N(E;q,0)$ structured polynomial without terminal link    
$D_{N-2}(E)$ interior principal determinant coefficient of $-\delta^2$    
$A_N(\Omega)$ $\frac{(N-1)!}{2^{N-2}}\Omega^{N-1}$ full-chain path coefficient    
$y$ $E/\sqrt q$ scaled eigenvalue    
$F_N(y)$ $\prod_{m=-j}^{j}(y-m)$ dimensionless structured polynomial    
$\zeta_N$ $A_N\delta/q^{N/2}$ crossover variable    
$\delta_c$ terminal-link crossover scale value at which $ \zeta_N $ is order one

Eigenvector and feasibility quantities

Symbol Definition Meaning        
$r$ $ \psi^{\mathsf T}\psi /(\psi^\dagger\psi)$ phase rigidity    
$K$ $r^{-2}$ Petermann factor        
$s$ characteristic eigenvalue displacement measured spectral splitting        
$\sigma$ $s/ \Omega $ dimensionless splitting    
$\eta$ $\sqrt{ q }/ \Omega $ dimensionless distance from the EP
$d$ $ \delta / \Omega $ dimensionless terminal coupling
$d_c$ $ \delta_c / \Omega $ dimensionless nominal crossover

The exact structured spectrum is

\[E_m=m\sqrt{\Omega^2-\gamma^2}.\]

Defining

\[q=\Omega^2-\gamma^2\]

compresses the spectrum to

\[E_m=m\sqrt q.\]

The quantity $q$ has dimensions of energy squared, angular frequency squared, or inverse-length squared, depending on the platform.

Sign of $q$ Interpretation
$q>0$ real structured spectrum
$q=0$ all structured eigenvalues coalesce
$q<0$ imaginary-conjugate structured levels

The crossover analysis approaches the exceptional point from

\[q\to0^+.\]

Without the terminal link,

\[P_N^{(0)}(E;q) = \prod_{m=-j}^{j}(E-m\sqrt q).\]

Introduce the scaled eigenvalue

\[E=\sqrt q\,y.\]

Every factor becomes

\[E-m\sqrt q = \sqrt q\,(y-m).\]

There are $N$ factors, so

\[P_N^{(0)}(E;q) =q^{N/2} \prod_{m=-j}^{j}(y-m).\]

Define

\[F_N(y)= \prod_{m=-j}^{j}(y-m).\]

Therefore

\[\boxed{ P_N^{(0)}(E;q)=q^{N/2}F_N(y) }.\]

This equation separates:

  1. the dimensional scale $q^{N/2}$,
  2. the dimensionless root geometry contained in $F_N(y)$.

The structure-breaking perturbation is

\[V_\delta = \delta \left( |1\rangle\langle N| +|N\rangle\langle1| \right).\]

It couples the first and last sites. The complete characteristic polynomial is

\[P_N(E;q,\delta) = P_N^{(0)}(E;q) -A_N(\Omega)\delta -\delta^2D_{N-2}(E).\]

This identity is exact for $N\ge3$. There are no terms proportional to $\delta^3,\delta^4,\ldots$ because the matrix contains only two entries proportional to $\delta$.

6. Deriving the Path Coefficient $A_N$

The linear term uses one terminal matrix element and the entire nearest-neighbour path through the array.

The product of all designed bonds is

\[\prod_{n=1}^{N-1}C_n = \prod_{n=1}^{N-1} \left[ \frac{\Omega}{2}\sqrt{n(N-n)} \right].\]

Separate the common factor:

\[\prod_{n=1}^{N-1}C_n = \left(\frac{\Omega}{2}\right)^{N-1} \left[ \prod_{n=1}^{N-1}n(N-n) \right]^{1/2}.\]

Now

\[\prod_{n=1}^{N-1}n=(N-1)!,\]

and after replacing $r=N-n$,

\[\prod_{n=1}^{N-1}(N-n) = \prod_{r=1}^{N-1}r =(N-1)!.\]

Therefore

\[\left[ \prod_{n=1}^{N-1}n(N-n) \right]^{1/2} =(N-1)!.\]

Hence

\[\prod_{n=1}^{N-1}C_n = \frac{(N-1)!}{2^{N-1}} \Omega^{N-1}.\]

There are two terminal directions, $1\to N$ and $N\to1$. Multiplying by two gives

\[\boxed{ A_N(\Omega) = \frac{(N-1)!}{2^{N-2}} \Omega^{N-1} }.\]

The factorial in the final crossover formula comes from this product of all engineered bonds.

Substitute

\[P_N^{(0)}=q^{N/2}F_N(y)\]

into the exact polynomial:

\[q^{N/2}F_N(y) -A_N\delta -\delta^2D_{N-2}(\sqrt q\,y) =0.\]

Divide by $q^{N/2}$:

\[F_N(y) = \frac{A_N\delta}{q^{N/2}} + \frac{\delta^2}{q^{N/2}} D_{N-2}(\sqrt q\,y).\]

This motivates

\[\boxed{ \zeta_N= \frac{A_N(\Omega)\delta}{q^{N/2}} }.\]

The numerator and denominator have the same dimensions:

\[[A_N\delta] = [E]^{N-1}[E] =[E]^N,\]

and

\[[q^{N/2}] = ([E]^2)^{N/2} =[E]^N.\]

Thus $\zeta_N$ is dimensionless.

8. Why the Quadratic Term Disappears from the Leading Scaling Equation

Hold $\zeta_N$ fixed while $q\to0^+$. From its definition,

\[\delta = \frac{q^{N/2}}{A_N}\zeta_N.\]

Therefore

\[\frac{\delta^2}{q^{N/2}} \sim q^{N/2}.\]

For fixed $N$ and bounded $y$, the interior determinant remains bounded. Consequently,

\[\frac{\delta^2}{q^{N/2}} D_{N-2}(\sqrt q\,y) \to0.\]

The universal leading equation is

\[\boxed{ F_N(y)=\zeta_N }.\]

The quadratic term is still included in every finite-$q$ calculation. It disappears only from the leading joint scaling limit.

9. Deriving the Crossover Scale in the Image

The structured regime corresponds to

\[|\zeta_N|\ll1,\]

and the terminal-link-dominated regime corresponds to

\[|\zeta_N|\gg1.\]
The crossover occurs when $ \zeta_N $ is of order one:
\[\left| \frac{A_N\delta_c}{q^{N/2}} \right| \sim1.\]
Solve for $ \delta_c $:
\[|\delta_c| \asymp \frac{|q|^{N/2}}{|A_N|}.\]

Using

\[|A_N| = \frac{(N-1)!}{2^{N-2}} |\Omega|^{N-1},\]

we obtain

\[\boxed{ |\delta_c| \asymp \frac{2^{N-2}}{(N-1)!} \frac{|q|^{N/2}}{|\Omega|^{N-1}} }.\]

This is the expression shown in the manuscript.

10. What the Symbol $\asymp$ Means

The symbol

\[\asymp\]

does not mean an exact equality at a uniquely defined physical boundary. Crossovers do not normally have a sharp universal edge.

It means that the two sides have the same leading scale. If one defines the nominal crossover by

\[|\zeta_N|=1,\]

then one may use the equality

\[|\delta_c|= \frac{2^{N-2}}{(N-1)!} \frac{|q|^{N/2}}{|\Omega|^{N-1}}.\]

Choosing $|\zeta_N|=1/2$ or $2$ changes only an order-one numerical prefactor, not the dependence on $q$, $\Omega$, or $N$.

11. Dimensionless Tolerance Formula

Define

\[\eta= \frac{\sqrt{|q|}}{|\Omega|}, \qquad d= \frac{|\delta|}{|\Omega|}.\]

Because

\[|q|^{N/2} = |\Omega|^N\eta^N,\]

the nominal crossover becomes

\[\frac{|\delta_c|}{|\Omega|} = \frac{2^{N-2}}{(N-1)!}\eta^N.\]

Thus

\[\boxed{ d_c= c_N\eta^N, \qquad c_N= \frac{2^{N-2}}{(N-1)!} }.\]

The first few coefficients are

$N$ $c_N$
3 $1$
4 $2/3$
5 $1/3$
6 $2/15$

The power $\eta^N$ makes the structured regime increasingly fragile for larger $N$.

12. Reading the $N=4$ Example

For $N=4$,

\[j=\frac32, \qquad m=-\frac32,-\frac12,\frac12,\frac32.\]

Therefore

\[F_4(y) = \left(y^2-\frac94\right) \left(y^2-\frac14\right).\]

Expanding,

\[F_4(y) = y^4-\frac52y^2+\frac9{16}.\]

The crossover equation is

\[F_4(y)=\zeta_4.\]

Treat this as a quadratic equation in $x=y^2$:

\[x^2-\frac52x+\frac9{16}-\zeta_4=0.\]

The solutions are

\[y^2= \frac54\pm\sqrt{1+\zeta_4}.\]

The inner pair reaches $y=0$ when

\[\frac54-\sqrt{1+\zeta_4}=0.\]

Therefore

\[\sqrt{1+\zeta_4}=\frac54,\]

and

\[\boxed{ \zeta_4=\frac9{16} }.\]

The paper separately checks that this double root has geometric multiplicity one and vanishing phase rigidity. It is therefore a secondary $\mathrm{EP}_2$.

13. Structured and Generic Limits from One Equation

The equation

\[F_N(y)=\zeta_N\]

contains both limiting responses.

Small $|\zeta_N|$

The roots remain close to the structured values $y=m$:

\[y_m = m+\frac{\zeta_N}{F_N'(m)}+\cdots.\]

Since $E=\sqrt q\,y$,

\[E_m\sim m\sqrt q.\]

Large $|\zeta_N|$

For large $ y $,
\[F_N(y)\sim y^N.\]

Therefore

\[y^N\sim\zeta_N.\]

Multiplying by $E=\sqrt q\,y$ gives

\[E^N \sim q^{N/2}\zeta_N = A_N\delta.\]

Hence

\[E\sim(A_N\delta)^{1/N}.\]

One scaled equation therefore interpolates between the square-root structured spectrum and the generic $N$th-root spectrum.

14. How the Eigenvector Quantities Connect

The paper also uses

\[r= \frac{|\psi^{\mathsf T}\psi|} {\psi^\dagger\psi}, \qquad K=r^{-2}.\]

Near the structured exceptional point,

\[r_{jm} \sim \binom{N-1}{j-m}^{-1} \left|\frac{q}{\Omega^2}\right|^{(N-1)/2}.\]

For a generic terminal-link unfolding,

\[r_{\mathrm g} \sim \left|\frac{\delta}{\Omega}\right|^{(N-1)/N}.\]

At the crossover,

\[|\delta_c| \sim |q|^{N/2},\]

so

\[|\delta_c|^{(N-1)/N} \sim |q|^{(N-1)/2}.\]

The two rigidity powers therefore match at the same crossover scale.

15. Paper-Reading Roadmap

Manuscript part Question answered
spin array and $\mathcal{PT}$ symmetry what is the ideal Hamiltonian?
structured perturbations why does a collective error give a square root?
structure-breaking terminal error why does a terminal link activate the full Jordan chain?
exact mixed polynomial where does $A_N$ come from?
crossover theorem how are $q$ and $\delta$ combined into $\zeta_N$?
$N=4$ example where does the secondary $\mathrm{EP}_2$ occur?
phase rigidity and robustness what happens to the eigenvectors?
$N=5$ taxonomy do other allowed errors give the same exponent?
feasibility section how small must an unwanted terminal link be?
appendices where are the detailed derivations and Maxima checks?

16. Common Notation Mistakes

Mistake Correct reading    
treating $q$ as an energy $q$ has dimensions of energy squared    
confusing $\epsilon$ and $\delta$ $\epsilon$ is structured; $\delta$ breaks the nearest-neighbour profile    
treating $y$ as a measured eigenvalue $y=E/\sqrt q$ is dimensionless    
treating $\zeta_N$ as a new physical coupling it is a dimensionless ratio of two competing polynomial terms    
reading $\asymp$ as exact equality it denotes a crossover scale    
forgetting the factor $(N-1)!$ it comes from the product of every designed bond    
using the terminal-link theorem for $N=2$ the structure-breaking terminal link is distinct only for $N\ge3$    
calling every repeated root an EP geometric multiplicity must also be checked    
writing $K\sim s^{-2(N-1)}$ with dimensional $s$ use $\sigma=s/ \Omega $

17. Final Connection Map

The whole paper can be remembered as the chain

\[(\Omega,\gamma) \longrightarrow q=\Omega^2-\gamma^2 \longrightarrow E=\sqrt q\,y \longrightarrow P_N^{(0)}=q^{N/2}F_N(y),\] \[C_1C_2\cdots C_{N-1} \longrightarrow A_N= \frac{(N-1)!}{2^{N-2}}\Omega^{N-1},\] \[\frac{A_N\delta}{q^{N/2}} \longrightarrow \zeta_N \longrightarrow F_N(y)=\zeta_N,\]

and finally

\[|\zeta_N|\sim1 \longrightarrow |\delta_c| \asymp \frac{2^{N-2}}{(N-1)!} \frac{|q|^{N/2}}{|\Omega|^{N-1}}.\]

Return to Part I: Non-Hermitian Arrays from First Principles or review Part IV: Petermann Factor from First Principles.

© Rajesh Kumar, SKMU · Physics Lecture Notes · rajeshphy.github.io

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