24 Jul 2025
T-dS Equations, Heat Capacities, and Joule-Kelvin Effect
Maxwell-relation response identities and throttling coefficients for ideal and van der Waals gases.
For a fixed-composition simple compressible system, the Maxwell relations turn entropy differentials into measurable response functions.
The two $T\,dS$ equations
Using $S=S(T,V)$,
\[dS=\left(\frac{\partial S}{\partial T}\right)_VdT +\left(\frac{\partial S}{\partial V}\right)_TdV.\]Since $(\partial S/\partial T)_V=C_V/T$ and $(\partial S/\partial V)_T=(\partial p/\partial T)_V$,
\[\boxed{T\,dS=C_V\,dT +T\left(\frac{\partial p}{\partial T}\right)_VdV}.\]With $(\partial p/\partial T)_V=\alpha/\kappa_T$,
\[\boxed{T\,dS=C_V\,dT+\frac{T\alpha}{\kappa_T}\,dV}.\]Using $S=S(T,p)$ and $(\partial S/\partial p)_T=-(\partial V/\partial T)_p=-V\alpha$ gives
\[\boxed{T\,dS=C_P\,dT-TV\alpha\,dp}.\]General value of $C_P-C_V$
Evaluate the first $T\,dS$ equation at constant pressure. Then $dV=V\alpha\,dT$ and $T\,dS=C_P\,dT$, so
\[C_P=C_V+T\left(\frac{\partial p}{\partial T}\right)_VV\alpha.\]Therefore
\[\boxed{C_P-C_V=\frac{TV\alpha^2}{\kappa_T}}.\]For the van der Waals molar equation
\[p=\frac{RT}{V_m-b}-\frac{a}{V_m^2},\]direct differentiation gives
\[\left(\frac{\partial p}{\partial T}\right)_{V_m} =\frac{R}{V_m-b},\] \[\left(\frac{\partial p}{\partial V_m}\right)_T =-\frac{RT}{(V_m-b)^2}+\frac{2a}{V_m^3}.\]Using $C_{P,m}-C_{V,m}=-T(p_T)^2/p_V$,
\[\boxed{C_{P,m}-C_{V,m} =\frac{R}{1-\dfrac{2a(V_m-b)^2}{RTV_m^3}}}.\]The ideal-gas limit $a,b\to0$ is $C_{P,m}-C_{V,m}=R$.
Joule-Kelvin coefficient
In steady throttling through a porous plug or valve, assume adiabatic walls, no shaft work, and negligible changes of bulk kinetic and gravitational potential energy. The steady-flow energy equation then gives
\[H_1=H_2.\]The Joule-Kelvin coefficient is
\[\mu_{\mathrm{JT}}=\left(\frac{\partial T}{\partial p}\right)_H.\]From
\[dH=C_P\,dT+ \left[V-T\left(\frac{\partial V}{\partial T}\right)_p\right]dp,\]set $dH=0$ to obtain
\[\boxed{\mu_{\mathrm{JT}} =\frac{T(\partial V/\partial T)_p-V}{C_P} =\frac{V}{C_P}(\alpha T-1)}.\]Its SI unit is $\mathrm{K\,Pa^{-1}}$. A pressure drop has $dp<0$: the gas cools when $\mu_{\mathrm{JT}}>0$ and warms when $\mu_{\mathrm{JT}}<0$.
For an ideal gas, $V=nRT/p$ and $\alpha=1/T$, so
\[\boxed{\mu_{\mathrm{JT}}=0}.\]For one mole of van der Waals gas, implicit differentiation at constant pressure gives
\[\left(\frac{\partial V_m}{\partial T}\right)_p =\frac{R/(V_m-b)} {RT/(V_m-b)^2-2a/V_m^3}.\]Hence the exact coefficient is
\[\boxed{ \mu_{\mathrm{JT}}= \frac1{C_{P,m}} \left[ \frac{TR/(V_m-b)}{RT/(V_m-b)^2-2a/V_m^3}-V_m \right]}.\]In the dilute, low-pressure limit $V_m\gg b$,
\[\boxed{\mu_{\mathrm{JT}}\simeq \frac1{C_{P,m}}\left(\frac{2a}{RT}-b\right)}.\]This approximation predicts an inversion temperature $T_i\simeq2a/(Rb)=2T_B$: below it attractions dominate and throttling cools; above it excluded volume dominates and throttling warms.
The linked Unit III Maxima worksheet verifies the van der Waals $C_P-C_V$ and exact Joule-Kelvin expressions. Every displayed symbolic residual is zero.
Solved Problems
1. Derive $(\partial V/\partial T)_p$ from an equation of state
Let the equation of state be written explicitly as $p=p(T,V)$. Its total differential is
\[dp=\left(\frac{\partial p}{\partial T}\right)_VdT +\left(\frac{\partial p}{\partial V}\right)_TdV.\]Along an isobar $dp=0$, so
\[\boxed{ \left(\frac{\partial V}{\partial T}\right)_p =-\frac{(\partial p/\partial T)_V} {(\partial p/\partial V)_T}}.\]For a stable ordinary fluid, the denominator is negative and the numerator is usually positive, giving positive thermal expansion. The derivative has units $\mathrm{m^3\,K^{-1}}$, as required.
2. Derive the dilute van der Waals Joule-Kelvin coefficient
Expand the molar equation through first order in density:
\[p\simeq\frac{RT}{V_m}+\frac{RTb-a}{V_m^2}.\]Solving perturbatively for volume at fixed $p$ gives
\[V_m\simeq\frac{RT}{p}+b-\frac{a}{RT}.\]Therefore
\[T\left(\frac{\partial V_m}{\partial T}\right)_p-V_m =T\left(\frac Rp+\frac{a}{RT^2}\right) -\left(\frac{RT}{p}+b-\frac{a}{RT}\right) =\frac{2a}{RT}-b.\]Hence
\[\boxed{\mu_{\mathrm{JT}}\simeq \frac{1}{C_{P,m}}\left(\frac{2a}{RT}-b\right)}.\]Both terms in parentheses have molar-volume units; division by $C_{P,m}$ gives $\mathrm{K\,Pa^{-1}}$. This is a low-pressure approximation and fails near condensation or the critical region.
Descriptive Questions
- Derive both $T\,dS$ equations and state the natural independent variables used in each.
- Explain why $C_P-C_V$ is nonnegative in a stable single phase.
- State the steady-flow assumptions that make a throttling process isenthalpic.
- Explain physically why an ideal gas has zero Joule-Kelvin coefficient.
Numerical Problems
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Find the molar value of $C_P-C_V$ for an ideal gas.
Final answer: $C_{P,m}-C_{V,m}=R=8.314\ \mathrm{J\,mol^{-1}K^{-1}}$.
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A system has $T=300\ \mathrm K$, $V=0.010\ \mathrm{m^3}$, $\alpha=3.0\times10^{-3}\ \mathrm{K^{-1}}$, and $\kappa_T=1.0\times10^{-5}\ \mathrm{Pa^{-1}}$.
Final answer: $C_P-C_V=TV\alpha^2/\kappa_T=2.70\ \mathrm{J\,K^{-1}}$.
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For carbon dioxide use $a=0.364\ \mathrm{Pa\,m^6\,mol^{-2}}$, $b=4.27\times10^{-5}\ \mathrm{m^3\,mol^{-1}}$, $C_{P,m}=37.1\ \mathrm{J\,mol^{-1}K^{-1}}$, and $T=300\ \mathrm K$ in the dilute formula.
Final answer: $\mu_{\mathrm{JT}}=6.72\times10^{-6}\ \mathrm{K\,Pa^{-1}}=0.672\ \mathrm{K\,bar^{-1}}$.
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Estimate the dilute inversion temperature for those van der Waals constants.
Final answer: $T_i=2a/(Rb)=2.051\times10^3\ \mathrm K$.
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A gas with $\mu_{\mathrm{JT}}=0.25\ \mathrm{K\,bar^{-1}}$ is throttled through a pressure drop of $20\ \mathrm{bar}$ within a range where $\mu_{\mathrm{JT}}$ is constant.
Final answer: $\Delta T=\mu_{\mathrm{JT}}\Delta p=-5.0\ \mathrm K$.
The $T\,dS$ and Joule-Kelvin Maxima worksheet verifies the implicit derivative, van der Waals limits, response identity, and all five numerical answers.
References
- Joule-Thomson effect, Wikipedia.
- M. W. Zemansky and R. H. Dittman, Heat and Thermodynamics, 7th ed., McGraw-Hill, 1997, chapters “Thermodynamic relations” and “Real gases.”
- P. Atkins, J. de Paula, and J. Keeler, Atkins’ Physical Chemistry, 11th ed., Oxford University Press, 2018, chapters “The first law” and “The properties of gases.”
Discussion