06 Jul 2025

Plasma Physics and Hydromagnetic Waves

Kinetic moments, plasma oscillations, Debye shielding, magnetic confinement, magnetoplasma equations, and Alfvén and magnetosonic waves.

mj-16 plasma-physics debye-shielding plasma-confinement alfven-waves magnetosonic-waves

A plasma is an ionized many-particle medium in which collective electric and magnetic forces are important. On scales much larger than its shielding length it is approximately quasineutral,

\[\sum_s q_sn_s\simeq0,\]

although small charge separations produce plasma oscillations and shielding.

Moments of the Boltzmann equation

For species $s$, let $f_s(\mathbf r,\mathbf v,t)$ be the number-density distribution in phase space. Its kinetic equation is

\[\frac{\partial f_s}{\partial t} +\mathbf v\cdot\nabla f_s +\frac{q_s}{m_s}(\mathbf E+\mathbf v\times\mathbf B) \cdot\nabla_{\mathbf v}f_s=C_s[f].\]

Define the density, mean velocity, pressure tensor, and heat flux by

\[n_s=\int f_s\,d^3v, \qquad n_s\mathbf u_s=\int\mathbf v f_s\,d^3v,\] \[\mathsf P_s=m_s\int (\mathbf v-\mathbf u_s)(\mathbf v-\mathbf u_s)f_s\,d^3v,\] \[\mathbf q_s=\frac{m_s}{2}\int \lvert\mathbf v-\mathbf u_s\rvert^2(\mathbf v-\mathbf u_s)f_s\,d^3v.\]

Assume $f_s$ decreases fast enough as $\lvert\mathbf v\rvert\to\infty$ that all velocity-space surface terms vanish.

Integrating the kinetic equation over velocity gives

\[\frac{\partial n_s}{\partial t} +\nabla\cdot(n_s\mathbf u_s) =\int C_s\,d^3v.\]

Number-conserving collisions make the right side zero, so

\[\boxed{ \partial_t n_s+\nabla\cdot(n_s\mathbf u_s)=0. }\]

For the first moment, multiply by $m_sv_i$ and integrate. The second velocity moment separates as

\[m_s\int v_iv_jf_s\,d^3v =m_sn_su_{si}u_{sj}+P_{s,ij}.\]

Integration by parts in velocity gives

\[q_s\int v_i(\mathbf E+\mathbf v\times\mathbf B)_j \frac{\partial f_s}{\partial v_j}\,d^3v =-q_sn_s[\mathbf E+\mathbf u_s\times\mathbf B]_i.\]

Moving this term to the right and using the continuity equation yields

\[\boxed{ m_sn_s(\partial_t+\mathbf u_s\cdot\nabla)\mathbf u_s =q_sn_s(\mathbf E+\mathbf u_s\times\mathbf B) -\nabla\cdot\mathsf P_s+\mathbf R_s, }\]

where $\mathbf R_s=m_s\int\mathbf vC_s\,d^3v$ is collisional momentum transfer.

Multiplication by $m_sv^2/2$ gives the energy moment. For isotropic pressure $\mathsf P_s=p_s\mathsf I$ and internal-energy density $\varepsilon_s=3p_s/2$,

\[\boxed{ \partial_t\!\left(\frac12m_sn_su_s^2+\varepsilon_s\right) +\nabla\cdot\!\left[ \left(\frac12m_sn_su_s^2+\varepsilon_s+p_s\right)\mathbf u_s +\mathbf q_s\right] =q_sn_s\mathbf E\cdot\mathbf u_s+Q_s. }\]

Here the collisional energy-transfer density is

\[\boxed{Q_s=\frac{m_s}{2}\int v^2C_s\,d^3v,}\]

with units $\mathrm{J\,m^{-3}\,s^{-1}}$ under the stated convention for $C_s$. The heat flux $\mathbf q_s$ carries units $\mathrm{W\,m^{-2}}$. The magnetic force does no work because $\mathbf u_s\cdot(\mathbf u_s\times\mathbf B)=0$.

Plasma oscillation

Consider cold electrons of equilibrium density $n_0$ displaced by $\xi$ relative to stationary ions. The two exposed charge sheets produce

\[E=\frac{en_0}{\epsilon_0}\xi\]

directed from the ion sheet to the electron sheet. The electron force is $-eE$, hence

\[m_e\ddot\xi=-\frac{n_0e^2}{\epsilon_0}\xi.\]

Therefore

\[\boxed{ \ddot\xi+\omega_{pe}^2\xi=0, \qquad \omega_{pe}=\sqrt{\frac{n_0e^2}{m_e\epsilon_0}}. }\]

$\omega_{pe}$ is in radians per second. Ion motion was neglected because $m_i\gg m_e$, and thermal pressure was neglected in this cold-plasma limit.

Debye shielding

Place a test charge $Q$ at the origin in an electron plasma with fixed ion background. Thermal equilibrium gives the electron density

\[n_e=n_0\exp\!\left(\frac{e\phi}{k_BT_e}\right) \simeq n_0\left(1+\frac{e\phi}{k_BT_e}\right),\]

where the linearization requires $\lvert e\phi\rvert\ll k_BT_e$. Thus, away from the test charge,

\[\rho=e(n_i-n_e)\simeq-\frac{n_0e^2}{k_BT_e}\phi.\]

Including the point source in Poisson’s equation gives

\[\nabla^2\phi-\frac{\phi}{\lambda_D^2} =-\frac{Q}{\epsilon_0}\delta^3(\mathbf r), \qquad \boxed{\lambda_D=\sqrt{\frac{\epsilon_0k_BT_e}{n_0e^2}}}.\]

For $r>0$, spherical symmetry gives

\[\frac1{r^2}\frac d{dr}\left(r^2\frac{d\phi}{dr}\right) -\frac{\phi}{\lambda_D^2}=0.\]

Writing $u=r\phi$ reduces this to $u^{\prime\prime}-u/\lambda_D^2=0$. The boundary condition $\phi\to0$ at infinity removes the growing exponential. Integrating Poisson’s equation over a vanishing sphere fixes $-4\pi r^2\epsilon_0\phi^{\prime}(r)\to Q$, so

\[\boxed{ \phi(r)=\frac{Q}{4\pi\epsilon_0r}e^{-r/\lambda_D}. }\]

Shielding is collective when a Debye sphere contains many particles, $N_D=(4\pi/3)n_0\lambda_D^3\gg1$.

The shielding and oscillation scales are linked. With the explicitly defined electron thermal speed $v_{Te}=\sqrt{k_BT_e/m_e}$,

\[\lambda_D\omega_{pe} =\sqrt{\frac{\epsilon_0k_BT_e}{n_0e^2}} \sqrt{\frac{n_0e^2}{m_e\epsilon_0}} =\boxed{v_{Te}}.\]

Thus an electron moving at the thermal-speed scale crosses one Debye length in approximately one inverse plasma frequency. Both sides have SI units of metres per second.

Magnetic confinement and magnetoplasma motion

For a uniform field $\mathbf B=B_0\hat{\mathbf z}$ and no electric field,

\[m_s\dot{\mathbf v}=q_s\mathbf v\times\mathbf B\]

gives

\[\dot v_x=\Omega_sv_y, \qquad \dot v_y=-\Omega_sv_x, \qquad \dot v_z=0, \qquad \Omega_s=\frac{q_sB_0}{m_s}.\]

Hence $v_x^2+v_y^2$ is constant and the orbit is circular with

\[\boxed{ \omega_{cs}=\frac{\lvert q_s\rvert B_0}{m_s}, \qquad r_{Ls}=\frac{v_\perp}{\omega_{cs}}. }\]

The sign of $q_s$ fixes the sense of rotation. A uniform magnetic field confines perpendicular motion but not motion parallel to the field. In a slowly varying field, $r_L\ll B/\lvert\nabla B\rvert$, the magnetic moment

\[\mu_m=\frac{m_sv_\perp^2}{2B}\]

is approximately conserved. With total kinetic energy also constant, a particle entering a stronger field is reflected when its parallel velocity reaches zero. If $B_0$ and pitch angle $\alpha_0$ are specified at entry and $B_m$ at the mirror,

\[\boxed{\sin^2\alpha_0\ge\frac{B_0}{B_m}}\]

is the mirror-confinement condition.

Fundamental magnetohydrodynamic equations

On scales long compared with kinetic lengths, a conducting plasma may be described by mass density $\rho_m$, bulk velocity $\mathbf u$, pressure $p$, and magnetic field $\mathbf B$. Ideal magnetohydrodynamics uses

\[\partial_t\rho_m+\nabla\cdot(\rho_m\mathbf u)=0,\] \[\rho_m(\partial_t+\mathbf u\cdot\nabla)\mathbf u =-\nabla p+\frac1{\mu_0}(\nabla\times\mathbf B)\times\mathbf B,\] \[\partial_t\mathbf B=\nabla\times(\mathbf u\times\mathbf B), \qquad \nabla\cdot\mathbf B=0,\] \[\mathbf E+\mathbf u\times\mathbf B=0, \qquad (\partial_t+\mathbf u\cdot\nabla) \left(\frac{p}{\rho_m^{\Gamma}}\right)=0.\]

These equations assume high conductivity, negligible displacement current, and a fluid scale much larger than particle gyro-radii.

Alfvén and magnetosonic waves

Linearize about a uniform static state $(\rho_0,p_0,\mathbf u_0=0,\mathbf B_0)$ and take every perturbation proportional to $e^{i(\mathbf k\cdot\mathbf r-\omega t)}$. Put

\[v_A=\frac{B_0}{\sqrt{\mu_0\rho_0}}, \qquad c_s=\sqrt{\frac{\Gamma p_0}{\rho_0}}, \qquad \cos\theta=\frac{\mathbf k\cdot\mathbf B_0}{kB_0}.\]

The linearized continuity and pressure equations give

\[\rho_1=\frac{\rho_0}{\omega}\mathbf k\cdot\mathbf u_1, \qquad p_1=c_s^2\rho_1.\]

The induction equation gives

\[\mathbf B_1=-\frac1\omega \mathbf k\times(\mathbf u_1\times\mathbf B_0) =\frac1\omega [\mathbf B_0(\mathbf k\cdot\mathbf u_1) -\mathbf u_1(\mathbf k\cdot\mathbf B_0)].\]

Choose $\mathbf B_0=B_0\hat{\mathbf z}$ and put $\mathbf k$ in the $xz$- plane. The $y$ component decouples from compression. The linearized momentum equation becomes

\[(\omega^2-k^2v_A^2\cos^2\theta)u_y=0,\]

so the shear Alfvén wave has

\[\boxed{\omega^2=k^2v_A^2\cos^2\theta.}\]

The coupled $x,z$ components are

\[\begin{pmatrix} \omega^2-k^2v_A^2-k^2c_s^2\sin^2\theta &-k^2c_s^2\sin\theta\cos\theta\\ -k^2c_s^2\sin\theta\cos\theta &\omega^2-k^2c_s^2\cos^2\theta \end{pmatrix} \begin{pmatrix}u_x\\u_z\end{pmatrix}=0.\]

A nonzero displacement requires the determinant to vanish:

\[\boxed{ \omega^4-k^2(v_A^2+c_s^2)\omega^2 +k^4v_A^2c_s^2\cos^2\theta=0. }\]

The fast and slow magnetosonic phase speeds are therefore

\[\boxed{ v_{f,s}^2=\frac12\left[ v_A^2+c_s^2 \pm\sqrt{(v_A^2+c_s^2)^2-4v_A^2c_s^2\cos^2\theta} \right]. }\]

For propagation parallel to $\mathbf B_0$, the two compressive speeds reduce to $v_A$ and $c_s$, while the shear Alfvén speed is $v_A$. For perpendicular propagation, the fast speed is $\sqrt{v_A^2+c_s^2}$; both the slow and shear Alfvén frequencies vanish in ideal MHD.

Equation-generated angular phase speeds of fast and slow magnetosonic waves and the shear Alfven wave
The plotted branches use \(c_s=0.6v_A\) and the exact dispersion relations above, from parallel to perpendicular propagation.

Solved Problems

1. Debye length and the collective-plasma test

An electron plasma has $n_0=1.00\times10^{18}\ \mathrm{m^{-3}}$ and $k_BT_e=2.00\ \mathrm{eV}$. Find $\lambda_D$, the number of electrons in a Debye sphere, and the screened-to-unscreened potential ratio at $r=3\lambda_D$.

Convert the thermal energy before using SI units:

\[k_BT_e=(2.00)(1.602176634\times10^{-19}) =3.20435\times10^{-19}\ \mathrm J.\]

Then

\[\begin{aligned} \lambda_D &=\sqrt{\frac{\epsilon_0k_BT_e}{n_0e^2}}\\ &=\sqrt{\frac{(8.85419\times10^{-12})(3.20435\times10^{-19})} {(1.00\times10^{18})(1.60218\times10^{-19})^2}}\\ &=1.0513\times10^{-5}\ \mathrm m=10.513\ \mathrm{\mu m}. \end{aligned}\]

The argument of the square root has units $\mathrm{m^2}$. The Debye-sphere population is

\[N_D=\frac{4\pi}{3}n_0\lambda_D^3 =4.867\times10^3\gg1,\]

so the collective description is self-consistent. At $r=3\lambda_D$,

\[\frac{\phi_{\rm screened}}{\phi_{\rm Coulomb}} =e^{-r/\lambda_D}=e^{-3}=0.04979.\]

Screening has reduced the potential to about five per cent of its Coulomb value, while the linearized Boltzmann treatment still additionally requires $\lvert e\phi\rvert\ll k_BT_e$.

2. Oblique magnetohydrodynamic wave speeds

For $v_A=200\ \mathrm{km\,s^{-1}}$, $c_s=100\ \mathrm{km\,s^{-1}}$, and $\theta=60.0^\circ$, calculate the fast, slow, and shear-Alfvén phase speeds.

Here $\cos\theta=1/2$. The discriminant in the magnetosonic formula is

\[\begin{aligned} D&=\sqrt{(v_A^2+c_s^2)^2 -4v_A^2c_s^2\cos^2\theta}\\ &=\sqrt{(50000)^2-4(200^2)(100^2)\left(\frac12\right)^2}\\ &=45825.8\ \mathrm{(km\,s^{-1})^2}. \end{aligned}\]

Therefore

\[v_f=\sqrt{\frac{50000+45825.8}{2}} =218.890\ \mathrm{km\,s^{-1}},\] \[v_s=\sqrt{\frac{50000-45825.8}{2}} =45.685\ \mathrm{km\,s^{-1}}.\]

The shear mode has

\[v_{\rm shear}=v_A\lvert\cos\theta\rvert =100.000\ \mathrm{km\,s^{-1}}.\]

All three speeds are real because the equilibrium is ideal and the discriminant is nonnegative. The results approach the stated parallel and perpendicular limits as $\theta$ tends to $0$ and $\pi/2$.

Descriptive Questions

  1. Obtain the continuity, momentum, and energy equations as successive velocity moments of the Boltzmann equation, identifying every vanishing surface term and collisional moment.
  2. Derive the cold electron plasma frequency from a small charge displacement and state precisely why thermal pressure and ion motion may be neglected.
  3. Derive the Debye-screened potential from the linearized Boltzmann density, including the boundary condition at infinity and the point-charge condition at the origin.
  4. Linearize the ideal magnetohydrodynamic equations about a uniform equilibrium and distinguish the polarization and propagation limits of shear-Alfvén, fast, and slow waves.

Numerical Problems

  1. Find $\omega_{pe}$ and $f_{pe}$ for an electron plasma with $n_e=5.00\times10^{17}\ \mathrm{m^{-3}}$.
  2. A proton with $v_\perp=3.00\times10^5\ \mathrm{m\,s^{-1}}$ moves in $B_0=0.200\ \mathrm T$. Find its angular gyrofrequency and Larmor radius.
  3. A magnetic mirror has $B_0=0.200\ \mathrm T$ and $B_m=1.80\ \mathrm T$. Find the minimum entry pitch angle for confinement.
  4. In an ideal plasma, $\mathbf u=2.00\times10^4\hat{\mathbf x}\ \mathrm{m\,s^{-1}}$ and $\mathbf B=5.00\times10^{-2}\hat{\mathbf z}\ \mathrm T$. Find $\mathbf E$.
  5. A proton plasma has $n_i=1.00\times10^{18}\ \mathrm{m^{-3}}$ and $B_0=1.00\times10^{-2}\ \mathrm T$. Find $v_A$ and the frequency of a parallel shear-Alfvén wave of wavelength $10.0\ \mathrm m$.
  6. Isotropic electrons have $n_e=1.00\times10^{19}\ \mathrm{m^{-3}}$ and $k_BT_e=5.00\ \mathrm{eV}$. Find their scalar pressure and internal-energy density.

Answers: 1. $\omega_{pe}=3.989\times10^{10}\ \mathrm{rad\,s^{-1}}$, $f_{pe}=6.349\ \mathrm{GHz}$; 2. $\omega_{cp}=1.916\times10^7\ \mathrm{rad\,s^{-1}}$, $r_{Lp}=1.566\times10^{-2}\ \mathrm m$; 3. $\alpha_{0,\min}=19.471^\circ$; 4. $\mathbf E=+1.00\times10^3\hat{\mathbf y}\ \mathrm{V\,m^{-1}}$; 5. $v_A=2.181\times10^5\ \mathrm{m\,s^{-1}}$, $f=2.181\times10^4\ \mathrm{Hz}$; 6. $p_e=8.011\ \mathrm{Pa}$, $\varepsilon_e=12.016\ \mathrm{J\,m^{-3}}$.

The plasma-frequency relation, shielding equation, thermal-scale identity, gyro-speed conservation, mirror condition, MHD dispersion determinant, and all printed numerical answers are checked in the Maxima worksheet; every printed residual is zero.

References

© Rajesh Kumar, SKMU · Physics Lecture Notes · rajeshphy.github.io

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